Answer:
x = ¹/₂
y = 1
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}-4x+3y=1\\\:\:\:\:\:\:6x-y=2 \end{cases}[/tex]
Multiply the second equation by 3:
[tex]\implies 3 \cdot 6x-3 \cdot y = 3 \cdot 2[/tex]
[tex]\implies 18x-3y=6[/tex]
Add this to the first equation to eliminate the term in y:
[tex]\begin{array}{lrr}&-4x+3y & = 1\\+ & 18x-3y& = 6\\\cline{2-3} & 14x \phantom{-3x)} & = 7\end{array}[/tex]
Solve for x:
[tex]\begin{aligned}\implies 14x & = 7\\\\\dfrac{14x}{14} & = \dfrac{7}{14}\\\\\implies x & = \dfrac{1}{2}\end{aligned}[/tex]
Substitute the found value of x into the first equation and solve for y:
[tex]\begin{aligned}-4x+3y & =1\\x=\dfrac{1}{2}\implies -4\left(\dfrac{1}{2}\right)+3y & =1\\-\dfrac{4}{2}+3y & =1\\-2+3y & =1\\-2+3y+2 & =1+2\\ 3y & =3\\\dfrac{3y}{3} & =\dfrac{3}{3}\\\implies y & =1\end{aligned}[/tex]
Therefore, the solution to the given system of equations is:
x = ¹/₂ and y = 1
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