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Sagot :
The correct answer for volume would the krypton occupy are 29.8 mL , 5375 mL , 6.5 * 10^ 5 mL .
We can solve this problem by using Boyle's Law, which states that:
"For a fixed mass of an ideal gas kept at constant temperature, the pressure
of the gas is inversely proportional to its volume"
Mathematically:
pV = const. where
p is the pressure of the gas
V is its volume
We can rewrite the formula as
PiVi = P2V2
For the gas in this problem:
P=0.400atm is the initial pressure
Vi 75.0mL is the initial volume
765mm Hg 1.006am is the final pressure (using the conversion factor
1atm = 760atm )
Solving for V2, we find the final volume:
V 2 =p1vi/ p2 =(0.400) (75.0)/ 1.006 = 29.8mL
We can solve this part by using again the equation:
Where in this case we have:
p 1= 0.400at is the initial pressure
V_{1} = 75mL is the initial volume
p_{2} = 4, nm*H_{0} is the final pressure
Converting into atmospheres,
p_{2} = 4 Hg 7mm/d -0.00536m
And solving for V2, we find the final volume:
V_{2} = (p_{1}*V_{1})/p_{2} = ((0.4)(75))/0.0056 = 5357mL
e)
As before, we use Boyles' Law:
p{1}*V{1} = p{2}*V{2}
In this part we have:
p{1} = 0.4atm is the initial pressure of the gas
V{1} = 75mL is the initial volume of the gas
p{2} = 3.5 * 10 ^ - 2 torr
1 torr is equivalent to 1 mmHg, so the conversion factor is the same as before.
therefore the final pressure in atmospheres is:
p2=3.50 *10^-2 2mm Hg 760mmHg/atm 4.6-10-atm
And so, the final volume of the krypton gas is:
V{2} = (p{1}V{1})/p{2} = ((0.4)(75))/(4.6 * 10 ^ - 5) = 6.5 * 10 ^ 5 * mL.
Learn more about boyle's law here :-
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