Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
4.80 grams of oxygen will be release.
When heated in a closed container in the presence of a catalyst, potassium chlorate decomposes into potassium chloride and oxygen gas via the following reaction:
2KClO3(s) → 2KCl(s)+ 3O2(g)
mass of potassium chlorate = 12.25g
mole of KClO3 = 12.25/122.5 = 0.1 mol
2 mole KClO3 (consumed) = 3 mole O2 (produced)
1 mole KClO3 = 3/2 mole O2
0.1 mole KClO3 = 0.1*1.5 mole O2
= 0.15 mole O2
mass of O2 = 0.15 * 32 = 4.80 grams
4.80 grams of oxygen will be release.
Learn more about oxygen here:
https://brainly.com/question/13370320
#SPJ9
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.