Answer:
Length= 19 yd
Width= 15 yd
Step-by-step explanation:
The perimeter of a rectangle is the sum of the lengths of all its sides.
Mathematically, it can be represented as below:
[tex]\boxed{\text{Perimeter of rectangle}=2\text{(length}+\text{width)}}[/tex]
Define variables used:
Let the length and width of the rectangle be L and W yards respectively.
Form an equation:
Given that the length of the rectangle is 4 yards longer that the width,
L= W +4 -----(1)
Next, form another equation using information on the perimeter.
68= 2(L +W) -----(2)
Substitute equation (1) into (2):
68= 2(W +4 +W)
68= 2(2W +4)
Divide both sides by 2:
34= 2W +4
Subtract both sides by 4:
2W= 34 -4
2W= 30
Divide both sides by 2:
W= 30 ÷2
W= 15
Substitute W= 15 into (1):
L= 15 +4
L= 19
Therefore, the length and width of the rectangle is 19 and 15 yards respectively.
Additional:
For another question on perimeter of rectangle, check out: https://brainly.com/question/15528005
