charliethebest2002
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PLEASE ANSWERING THIS QUESTIONS!!

The length of a rectangle is two more than double the width. If the perimeter is 82 inches, find the dimensions.


The width is (Blank) inches.

The length is (Blank) inches.


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Sagot :

mahesharanthilini

[tex]\huge\mathcal {♨Answer♥}[/tex]

Let's get the width as [tex]\large\texttt {x}[/tex]

So,

The length of the rectangle is [tex]\large\texttt {2x +2}[/tex]

The perimeter of the rectangle is [tex]\large\texttt {82 inches}[/tex]

Let's get the answer for width,

☆ 2 (2x + 2) + 2x = 82

4x + 4 + 2x = 82

6x + 4 = 82 - 4

6x ÷ 6 = 78 ÷ 6

x = 13

Let's get the answer for length,

☆ 2x + 2

2 × 13 + 2

28

Then,

[tex]\large\texttt {↪The width is 13 inches}[/tex]

[tex]\large\texttt {↪The length is 28 inches}[/tex]

☆...hope this helps...☆

_♡_mashi_♡_

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