A) The distance that a force of 3 newtons would stretch the rubber band is; 0.015 m
B) The amount of work it takes to stretch the rubber band this far is; 0.0225 J
How to solve Hooke's Law?
From Hookes's law, as long as the elastic limit is not exceeded the extension is directly proportional to the force applied.
F = Ke
Where;
F = force
K = force constant
e = extension
Thus, for a restoring force of magnitude 2 newtons ;
2 N = K(1 × 10⁻²) m
K = 2 N /(1 × 10⁻²) m
K = 200 N/m
a) For a force of 3 newtons, we have;
3N = 200 N/m × a
Where a is the extension in meters
a = 3N/200 N/m
a = 0.015 m
b) The formula to find the work done is;
P.E = ¹/₂Ke²
P.E = ¹/₂ * 200 * 0.015²
P.E = 0.0225 J
Read more about Hooke's Law at; https://brainly.com/question/14495152
#SPJ1
