Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

solve for x
log(x–4)+log(x+3)=2logx

Sagot :

konrad509
[tex]D:x-4>0 \wedge x+3>0 \wedge x>0\\ D:x>4 \wedge x>-3 \wedge x>0\\ D:x>4\\\\ \log(x-4)+\log(x+3)=2\log x\\ \log(x-4)(x+3)=\log x^2\\ (x-4)(x+3)=x^2\\ x^2+3x-4x-12=x^2\\ -x=12\\ x=-12\\ -12\not\in D\\ \Downarrow\\ \boxed{x\in\emptyset}[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.