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A population has a mean = 79 and a standard deviation = 18. Find the mean and standard deviation of a sampling distribution of sampling means with sample size = 36.

Sagot :

The sampling distribution of sample means is a mean of 79 and a standard deviation of 3.

What is the standard deviation?

The standard deviation mathematical and statistical analysis tool used to explain the diversity of treatments or values around the Mean is the standard deviation, which is also known as the square root of variance.

Given that,

Population mean,  [tex]\bar{x}[/tex] = 79

Population standard deviation, σ = 18

Sample size, n = 36

We have to determine the mean and standard deviation of a sampling distribution of sample means.

Let X denotes a random variable distributed with a mean and standard deviation of 85 and 28 respectively.

Also, if a random sample of size n is drawn from the population, then the sample mean is denoted by [tex]\bar{x}[/tex].

The sampling distribution of sample means [tex]\bar{x}[/tex] is given by:

ц [tex]\bar{x}[/tex] = ц

σ [tex]\bar{x}[/tex]  = σ/√n

Therefore, for the sample size n = 36, the sampling distribution of sample means [tex]\bar{x}[/tex] is obtained as:

ц [tex]\bar{x}[/tex] = 79

σ [tex]\bar{x}[/tex]  = 18/√36 = 3

Hence, the required sampling distribution of sample means is mean of 79 and a standard deviation of 3.

Learn more about the standard deviation here:

brainly.com/question/14747159

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