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George wants 42 liters of a mixture of water and 15% lemon juice. he has a mixture of 5% lemon juice and a mixture of 20% lemon juice. how many liters of the 5% and 20% mixtures should he mix to get what he wants? (round you answer to the nearest tenth if necessary.)

Sagot :

The amount of 5% lemon juice mixture and 20% lemon juice mixture that needed to be mixed is 14 liters and 28 liters, respectively.

What are Percentages?

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Let the amount of 5% lemon juice mixture that is needed to be mixed be represented by x, then the amount of 20% lemon juice mixture will be represented by (42-x), because the total mixture is needed to be 42 liters.

Now, given that George wants 42 liters of a mixture of water and 15% lemon juice with a mixture of 5% lemon juice, and a mixture of 20% lemon juice. Therefore, we can write,

5% of x + 20% of (42-x) = 15% of 42 liters

0.05x + 0.2(42 - x) = (0.15×42)

0.05x + 8.4 - 0.2x = 6.3

0.05x - 0.2x = 6.3 - 8.4

-0.15x = -2.1

x = -2.1 / -0.15

x = 14

Further, the amount of mixture of lemon juice that is needed to be mixed can be written as,

  • 5% lemon juice mixture, x = 14 liters
  • 20% lemon juice mixture, (42 - x) = 28 liters

Hence, the amount of 5% lemon juice mixture and 20% lemon juice mixture that needed to be mixed is 14 liters and 28 liters, respectively.

Learn more about Percentages here:

https://brainly.com/question/6972121

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