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1/4(x-2) +4=12
how do i solve thisssss plssss help it’s for tmr


Sagot :

Answer:

x = 34

Step-by-step explanation:

1/4(x - 2) + 4 = 12

Subtract 4 from both sides.

1/4(x - 2) = 8

Multiply both sides by 4.

x - 2 = 32

Add 2 to both sides.

x = 34

   [tex]\bf{\dfrac{1}{4}(x-2)+4=12 }[/tex]

Use the distributive property to multiply 1/4 times x−2.

     [tex]\bf{\dfrac{1}{4}x+\dfrac{1}{4}(-2)+4=12 }[/tex]

Multiply 1/4 and −2 to get -2/4.

             [tex]\bf{\dfrac{1}{4}x+\dfrac{-2}{4}+4=12 }[/tex]

Reduce the fraction -2/4 to its minimum expression extracting and canceling 2.

             [tex]\bf{\dfrac{1}{4}x-\dfrac{1}{2}+4=12 }[/tex]

Convert 4 to the fraction 8/2.

               [tex]\bf{\dfrac{1}{4}x-\dfrac{1}{2}+\dfrac{8}{2} =12 }[/tex]

Since -1/2 and 8/2 have the same denominator, add their numerators to add them together.

                 [tex]\bf{\dfrac{1}{4}x+\dfrac{-1+8}{2 }=12 \ \ \longmapsto \ \ [Sum \ -1 \ and \ 8] }[/tex]

                      [tex]\bf{\dfrac{1}{4}x+\dfrac{7}{2 }=12 }[/tex]

Subtract 7/2 from both sides.

                         [tex]\bf{\dfrac{1}{4}x=12-\dfrac{7}{2} }[/tex]

Convert 12 to the fraction 24/2.

                         [tex]\bf{\dfrac{1}{4}x=\dfrac{24}{2}-\dfrac{7}{2} }[/tex]

Since 24/2 and 7/2 have the same denominator, subtract their numerators to subtract them.

            [tex]\bf{\dfrac{1}{4}x=\dfrac{24-7}{2} \ \ \longmapsto \ \ [Subtract \ 7 \ from \ 24] }[/tex]

                   [tex]\bf{\dfrac{1}{4}x=\dfrac{17}{2 }[/tex]

Multiply both sides by 4, the reciprocal of 1/4.

              [tex]\bf{x=\dfrac{17}{2}\times4 \ \longmapsto \ \ x=\dfrac{17\times4}{2} \ \ \ [Multiply \ 17 \ and \ 4.] }[/tex]

                            [tex]\bf{x=\dfrac{68}{2} \ \ \longmapsto \ \ \ [Split] }[/tex]

                               [tex]\red{\boxed{\bf{\blue{Answer \ \ \longmapsto \ \ x=34}}}}[/tex]

Skandar