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Sagot :
The mass of alcohol in one litre of the mixture is 371g
Calculation and Explanation
Let us assume the alcohol to be ethyl alcohol (C2H5OH) with the temperature being 20°C.
Given we have assumed this, the density of water and ethyl alcohol becomes,
ρa=789.45g/L
ρw=998.23gL
and then it is given that the density of the solution is ρs=900gL
We know that,
ρ= m/v
⇒ m=ρv
⇒m=ρs Vs = 900g
Then we see that the sum of the mass of ethyl alcohol and water is the same as 900g
But we are interested in finding the values keeping the volume as 1L
hence, Va +Vw =1
⇒ Vw = 1-Va
Then we know that
900g=Va(789.45g/L)+(1−Va)(998.23g/L)
so solving the equation for ethyl alcohol, we have.
Va = 0.4705 L
then to get the mass of ethyl alcohol,
ma= ρaVa
ma= (789.45g/L) (0.4705L)
ma= 371g
Thus, the mass of alcohol (ethyl alcohol) as calculated is 371g.
To know more about Ethyl alcohol, visit:
https://brainly.com/question/8950356
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