Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Number of train rides to make the frequent-rider pass a better deal than standard train tickets is 26 or more rides.
As given,
Cost of standard train ticket = 3 per ride
Price of frequent rider pass= 18.75 each month
Cost of ticket using rider pass = 2.25 per ride
let x be the number of rides
Equation:
18.75 + 2.25x < 3x
⇒ 0.75x > 18.75
⇒ x > 25
Therefore, number of train rides to frequent-rider pass a better deal than standard train tickets is 26 or more rides.
Learn more about numbers here
brainly.com/question/17429689
#SPJ4
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.