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Sagot :
The inequality for Leila claim is (0.75 × x) > (0.50 × y) and the support claim is x = 100 and y = 10 and that refutes the claim is x = 1 and y = 200
Inequality:
Inequality are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
Given,
Leila says that 75% of a number will always be greater than 50% of any other number.
Here we need to find the inequality and we also need to find one that supports Leila's claim and one to show that she is incorrect.
Let x and y be two numbers.
Leila says that 75% of a number will always be greater than 50% of any other number.
This means that the inequality is,
=> (0.75 × x) > (0.50 × y)
We know that,
75% of x = 0.75 × x
and
50% of y = 0.50 × y
So,
Numbers that support Leila's claim.
Let x = 100 and b = 10
=> 0.75 × x
=> 0.75 × 100 = 75
and
=> 0.50 × 10 = 5
As we know that, based in on the inequality,
=> 75 > 5
Hence, x = 100 and y = 10 support Leila's claim.
Similarly,
Numbers that refutes her claim.
Let x = 1 and y = 200
=> 0.75 × x
=> 0.75 × 1 = 0.75
and
=> 0.50 × 200 = 100
As we know that,
=> 0.75 < 100
Hence, x = 1 and y = 200 refutes Leila's claim.
To know more about Inequality here.
https://brainly.com/question/11612965
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