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Sagot :
The sample proportion, p-hat, of engineers who have master's degrees is 68.5% out of 200 engineers.
p-hat proportion:
In this proportion, "p" denotes the probability of a certain event occurring or a certain parameter being true for a certain population, but when a population is large, it may be impractical or impossible to measure it directly. So, we have used the proportion for that cases.
The general form for calculating p-hat proportion is,
[tex]\hat{p}=\frac{x}{y}[/tex]
where
x is the number of successes in the sample, and
y is the size of the sample.
Given,
In a random sample of 200 engineers, 137 have a master's degree.
Here we need to find the the sample proportion, p-hat, of engineers who have master's degrees
According to the question,
x = 137 (number of successes in the sample)
and y = 200 (size of the sample)
Now apply the value on the formula then we get,
[tex]\hat{p}=\frac{137}{200}[/tex]
So, the value of p-hat is
[tex]\hat{p}=0.685[/tex]
The results are usually reported as a percentage, which in this case would be
=> 0.685 x 100 = 68.5%
Therefore, the sample proportion, p-hat, of engineers who have master's degrees is 68.5% out of 200 engineers.
To know more about p-hat proportion here
https://brainly.com/question/1597320
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