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A baseball is popped straight up with an initial speed of 25.9 meters per second. What is the ball's velocity after it has traveled a total distance of 50.0 meters? Include units in your answer.

Sagot :

The ball's velocity after it has travelled a total distance of 50.0 meters is 40.63 m/s

Data obtained from the question

The following data were obtained from the question:

  • Initial velocity (u) = 25.9 m/s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) = 50 m
  • Final velocity (v) = ?

How to determine the final velocity

We can obtain the final velocity as illustrated below:

v² = u² + 2gh

v² = 25.9² + (2 × 9.8 × 50)

v² = 670.81 + 980

v² = 1650.81

Take the square root of both sides

v = √1650.81

v = 40.63 m/s

Thus, the velocity after travelling 50 m is 40.63 m/s

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