Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The distance travelled by the body on last second of its upwards journey is 4.935m
What is projectile motion?
A projectile is an object or particle that is launched toward the surface of the Earth and moves along a curved path only under the influence of gravity.
To solve this question, consider the horizontal distance to be H and
distance traveled by the body in the last second be d
[tex]H=U^{2} /2g[/tex]
[tex]H=100^{2} /2*9.8[/tex]
H=510.2m
Now time taken to reach a height of
510.2 m= [tex]\sqrt[n]{2H/g}[/tex]
=10.2 seconds
Now,
[tex]s=ut+1/2gt^{2}[/tex]
[tex]H-d= (100)(t-1)-1/2g(t-1)^{2}[/tex]
[tex]510.2-d=100*9.2-1/2*9.8*9.2^{2}[/tex]
d=4936m
So, the correct answer is '4.936m'.
To know more about projectile motion visit:
https://brainly.com/question/11049671
#SPJ4
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
