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Sagot :
The distance travelled by the body on last second of its upwards journey is 4.935m
What is projectile motion?
A projectile is an object or particle that is launched toward the surface of the Earth and moves along a curved path only under the influence of gravity.
To solve this question, consider the horizontal distance to be H and
distance traveled by the body in the last second be d
[tex]H=U^{2} /2g[/tex]
[tex]H=100^{2} /2*9.8[/tex]
H=510.2m
Now time taken to reach a height of
510.2 m= [tex]\sqrt[n]{2H/g}[/tex]
=10.2 seconds
Now,
[tex]s=ut+1/2gt^{2}[/tex]
[tex]H-d= (100)(t-1)-1/2g(t-1)^{2}[/tex]
[tex]510.2-d=100*9.2-1/2*9.8*9.2^{2}[/tex]
d=4936m
So, the correct answer is '4.936m'.
To know more about projectile motion visit:
https://brainly.com/question/11049671
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