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Sagot :
The correct answer is option 1.
From the accompanying photo,
Right triangle CAB has three sides.
Consequently, m1 = 90°.
Similarly, mACD = 90°
∠ACD = 90° = ∠ACB + ∠BCD
= m∠3 + m∠4 = 90°
Because m4 = 35°,
m∠3 + 35° = 90°
m∠3 = 90° - 35° = 55°
In the ABC triangle,
∠ACB + ∠CBA + ∠BAC = 180° [triangle property]
∠3 + ∠2 + ∠1 = 180°
55° + ∠2 + 90° = 180°
∠2 + 145° = 180°
∠2 = 180° - 145° = 35°
Because ABCDBC is a transversal,
The lines are referred to as transversal lines when a straight line crosses two or more parallel lines. Any time this transverse line crosses a coplanar line, alternate angles—also referred to as exterior or interior alternate angles—are created.
In light of this, ∠2 = ∠4 = 35° [Alternate Interior Angles].
To learn more about Alternate Interior Angles refer the link:
https://brainly.com/question/17991546
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