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Sagot :
The expression for the area within the circle but outside the triangle as a function of the length 3x of the side of the triangle is [tex]\frac{88r^2}{7}-\frac{9\sqrt{3} }{2}x^2[/tex].
It is given that:-
Radius of circle = 2r
Length of side of equilateral triangle = 3x
We have to find the expression for the area within the circle but outside the triangle as a function of the length 3x of the side of the triangle.
We know that,
Area of circle = [tex]\pi R^2[/tex]
Where R is the radius of the circle.
We have R = 2r
Area of an equilateral triangle = [tex]\frac{\sqrt{3} }{2}a^2[/tex]
Where, a is the length of side of equilateral triangle.
a = 3x
Hence,
Expression = [tex]\pi R^2-\frac{\sqrt{3} }{2}a^2[/tex]
Expression = [tex]\frac{22}{7}*(2r)^2-\frac{\sqrt{3} }{2}*(3x)^2 = \frac{88r^2}{7}-\frac{9\sqrt{3} }{2}x^2[/tex].
To learn more about area of an equilateral triangle, here:-
https://brainly.com/question/10681095
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