Answered

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Write an expression for the area of a rectangle if the length is 2x^2-3x+1 and the width is x-2.

Sagot :

The expression for the area of a rectangle is [tex]2x^3-7x^2+6x-2[/tex].

It is given in the question that the length of the rectangle is [tex]2x^2-3x+1[/tex] and width is (x - 2).

We have to find a expression for the area of a rectangle.

We know that,

Area of a rectangle = l * b

Where,

l represents the length of the rectangle

b represents the breadth of the rectangle

Hence, using the data given in the question, we can write,

Area of a rectangle = [tex](2x^2-3x+1)*(x-2)[/tex]

Area of a rectangle = [tex](2x^3)+(-4x^2)+(-3x^2)+(6x)+(-2)[/tex]

Area of a rectangle = [tex]2x^3-7x^2+6x-2[/tex]

To learn more about area of a rectangle, here:-

https://brainly.com/question/20693059

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