Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The hotel charge in city one is $767 and the hotel charge in city two is $2276.
Let x = the charge in 1st city before taxes and
Let y = the charge in 2nd city before taxes
The equation before taxes:
y = x ₊ 1500 ..eq(1)
The equation for total tax paid:
0.075x ₊ 0.055y = 700 ..eq(2)
Substitute equation 1 that is y value in equation 2.
0.075x ₊ 0.055(x₊1500) = 700
0.075x ₊ 0.055x ₊ 82.5 = 700
add the variables and subtract the constants.
0.805x = 700 ₋ 82.5
0.805x = 617.5
x = 617.5/0.805
x = 767
now substitute x value in equation 1.
y = 767 ₊ 1500
y = 2267
Hence the hotel charge before the tax in the first city was $767 and in the second city was $2267.
Learn more about Linear equations here:
brainly.com/question/1884491
#SPJ9
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.