At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The hotel charge in city one is $767 and the hotel charge in city two is $2276.
Let x = the charge in 1st city before taxes and
Let y = the charge in 2nd city before taxes
The equation before taxes:
y = x ₊ 1500 ..eq(1)
The equation for total tax paid:
0.075x ₊ 0.055y = 700 ..eq(2)
Substitute equation 1 that is y value in equation 2.
0.075x ₊ 0.055(x₊1500) = 700
0.075x ₊ 0.055x ₊ 82.5 = 700
add the variables and subtract the constants.
0.805x = 700 ₋ 82.5
0.805x = 617.5
x = 617.5/0.805
x = 767
now substitute x value in equation 1.
y = 767 ₊ 1500
y = 2267
Hence the hotel charge before the tax in the first city was $767 and in the second city was $2267.
Learn more about Linear equations here:
brainly.com/question/1884491
#SPJ9
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.