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The perimeter of a rectangle is 32 m. The length is 4 m more than two times the width. Find the length and the width of the rectangle.

Sagot :

varshamittal029

The length of the rectangle is 12 meters and its width is 4 meters.

A rectangle is a four sided figure, whose opposite sides are equal and the angle formed by any two adjacent sides is 90 degrees.

Here, we are given that the perimeter of the rectangle is 32 meters.

Let the length of the rectangle be L and breadth or width be B

We known that perimeter of a rectangle = 2(L + B)

Now, it is given that the length is 4 m more than two times the width

ā‡’ L = 4 + 2B

Thus, the area of the perimeter will be-

Perimeter = 2(4 + 2B + B)

ā‡’ 32 = 2(4 + 2B + B)

32/2 = 4 + 2B + B

16 = 4 + 3B

16 - 4 = 3B

12 = 3B

or 3B = 12

B = 12/3

B = 4

Thus, the width of the rectangle is 4 meters.

Therefore, L = 4 + 2(4)

L = 4 + 8

L = 12

Thus, the length of the rectangle is 12 meters.

Learn more about rectangles here-

https://brainly.com/question/24571594

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