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Sagot :
Answer:
- 385 mph
- 350 mph
Step-by-step explanation:
You want the individual speeds of airplanes that close the 2940 mile distance between them in 4 hours, and have a speed difference of 35 mph.
Setup
The closing speed is found using the relation ...
speed = distance/time
It is ...
(2940 mi)/(4 h) = 735 mi/h
If x represents the speed of the slower plane, then (x+35) is the speed of the faster one. The sum of their speeds is the closing speed:
x +(x +35) = 735
Solution
Simplifying, we have ...
2x +35 = 735
2x = 700 . . . . . . subtract 35
x = 350 . . . . . . . divide by 2
x+35 = 385 . . . . speed of the faster plane
The speeds of the planes are 350 mph and 385 mph.
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