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twice a number increased by three is between negative three and seven

Sagot :

varshamittal029

The number can be -3, -2, -1, 0 ,1

Here, we are given that twice a number is increased by three and the result is between negative three and seven.

Let the number be x

Twice of the number = 2x

Four more than twice the number = 2x + 4

This number is between -3, 7

⇒ -3 < 2x +4 < 7

subtracting 4 from both sides we get

-3 -4 < 2x < 7 - 4

-7 < 2x < 3

Dividing both sides by 2 we get

-7/2 < x < 3/2

- 3.5 < x < 1.5

Thus the original number lies between -3.5 and 1.5

This means that it can take 5 values-

-3, -2, -1, 0 ,1

Learn more about inequalities here-

https://brainly.com/question/24372553

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