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Calculate the mass of potassium hydroxide, KOH, required to prepare 174.59 cm3 of a 0.864 mol dm-3 solution.

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CintiaSalazar

Taking into account the definition of molar concentration and molar mass, the mass of potassium hydroxide, KOH, required to prepare 174.59 cm³ of a 0.864 mol/dm³ solution is 8.45988 grams.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by:

Molarity= number of moles÷ volume

Definition of molar mass

The molar mass of substance is defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Mass of potassium hydroxide

In this case, you know that:

  • Molarity= 0.864 mol/dm³
  • Volume= 174.59 cm³= 0.17459 dm³ (being 1 cm³= 0.001 dm³)

Replacing in the definition of molar concentration:

0.864 mol/dm³= number of moles÷ 0.17459 dm³

Solving:

0.864 mol/dm³ ×0.17459 dm³= number of moles

0.1508 mol= number of moles

The molar mass of KOH is 56.1 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 56.1 grams, 0.1508 moles of the compound contains how much mass?

mass= (0.1508 moles×56.1 grams)÷ 1 moles

mass= 8.45988 grams

In summary, the mass of potassium hydroxide, KOH, required to prepare 174.59 cm³ of a 0.864 mol/dm³ solution is 8.45988 grams.

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