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Sagot :
28 grams of iron will be needed to react completely to form 40 grams of iron oxide.
The atomic mass of iron, 2 Fe = 112
The molecular mass of iron oxide (III) = 160
We have to find how many grams of iron are required to form 40 grams of iron oxide.
By using the comparison formula, we get,
The atomic mass of iron/ Molecular mass of iron oxide = Mass of iron/mass of iron oxide.
Mass of iron = 112/160 × 40
Or, the mass of iron = 28grams.
Therefore, 28 grams of iron will be required to react completely to form 40 grams of iron oxide.
To learn more about iron oxide, visit: https://brainly.com/question/18500540
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