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Sagot :
The first flight is 2 hours and second flight is 2 hours and 48 minutes
The two distances are the same (out and back),
so set them equal.
That distance is cover by having one is (rate)(time) equal to other is (rate)(time).
Let,
One time is “x” and the other is “4.8-x.”
One average rate is 460 per hour
and the other average rate is 500 per hour.
we know , Speed = [tex]\frac{distance}{time}[/tex]
so , distance = speed × time
put in this formula we get the value of X
⇒460 x = 500 (4.8 -x)
⇒460 x = 2400 - 500x
⇒900 x = 2400
⇒x = 2.5 hours for the slower plane.
⇒4.8- x = 2.3 hours for the faster plane.
The formula speed = distance ÷ time can be rearranged, just like any other equation.
Here detail explanation about relation between speed distance and time :
The formula can be rearranged in three ways:
speed = distance ÷ time
distance = speed × time
time = distance ÷ speed
To calculate one of the variables (speed, distance or time) we need the other two.
Learn more about Speed distance and time here: brainly.in/question/32093105
SPJ9
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