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la suma de los primeros n enteros positivos es un numero de tres digitos iguales. cual es la suma de los digitos de n?

Sagot :

bharathparasad577

The sum of n natural numbers is three digits number and all digits are the same. The same digits is 6 and the sum is 666.

A three-digit number with the same digits is the sum of n natural numbers.

Let's say the sum of n natural numbers is bbb.

Then,

n( n + 1) / 2 = bbb

n( n + 1) / 2 = b( 111 )

n( n + 1) / 2 = b ( 3 × 37 )

n( n + 1) = 6b × 37

Now, the left-hand side of the equation is the product of two consecutive natural numbers.

Therefore, the right-hand side of the equation is also the product of two consecutive natural numbers.

Hence, 6b = 36

b = 36/ 6

b = 6 and n = 36

As a result, 36 numbers have been added together, and their total is 666.

Learn more about natural numbers here:

https://brainly.com/question/2228445

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