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Sagot :
Perimeter of rectangle is 9.5 inches
If the length of the rectangle is l and its width is w,
l = 4w + 1, and
lw = (4w+1)×w = 3.
This yields 4w² + 1w -3= 0, which can be solved in the normal way for quadratic equations.
Solving the equation we get as
w=0.75 or w=-1
as it an not be negative value hence w=0.75
l=4
Perimeter of rectangle is 2*(l+w)= 9.5 inches.
Learn more about rectangle here:
https://brainly.com/question/16021628
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