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Sagot :

The equations ordered from the least to greatest is

y = (-3/4)x + 2

y - 3 = 1/2(x - 4)

3x - 4y = 7

y = 12(x - 19) + 5

Order of equations

From the question, we are to order the equations from least to greatest by the value of the slope

The given equations are

y = (-3/4)x + 2

3x - 4y = 7

y = 12(x - 19) + 5

y - 3 = 1/2(x - 4)

To determine the slopes of the line, we will compare the equations to the general form of the equation of a line

The general form of the equation of a line is

y = mx + b

Where m is the slope

and b is the y-intercept

  • y = (-3/4)x + 2

By comparison,

m = -3/4

∴ Slope = -3/4

  • 3x - 4y = 7

First, rearrange

3x - 7 = 4y

4y = 3x - 7

y = (3/4)x - 7/4

By comparison,

m = 3/4

∴ Slope = 3/4

  • y = 12(x - 19) + 5

First, simplify

y = 12x - 228 + 5

y = 12x - 223

By comparison,

m = 12

∴ Slope = 12

y - 3 = 1/2(x - 4)

First, simplify

y - 3= (1/2)x - 2

y = (1/2)x -2 + 3

y = (1/2)x + 1

By comparison,

m = 1/2

∴ Slope = 1/2

Now,

The slopes ordered from the least to greatest is

-3/4 < 1/2 < 3/4 < 12

Thus,

The equations ordered from the least to greatest is

y = (-3/4)x + 2

y - 3 = 1/2(x - 4)

3x - 4y = 7

y = 12(x - 19) + 5

Learn more on Order of equations here: https://brainly.com/question/9353038

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