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Sagot :
The equations ordered from the least to greatest is
y = (-3/4)x + 2
y - 3 = 1/2(x - 4)
3x - 4y = 7
y = 12(x - 19) + 5
Order of equations
From the question, we are to order the equations from least to greatest by the value of the slope
The given equations are
y = (-3/4)x + 2
3x - 4y = 7
y = 12(x - 19) + 5
y - 3 = 1/2(x - 4)
To determine the slopes of the line, we will compare the equations to the general form of the equation of a line
The general form of the equation of a line is
y = mx + b
Where m is the slope
and b is the y-intercept
- y = (-3/4)x + 2
By comparison,
m = -3/4
∴ Slope = -3/4
- 3x - 4y = 7
First, rearrange
3x - 7 = 4y
4y = 3x - 7
y = (3/4)x - 7/4
By comparison,
m = 3/4
∴ Slope = 3/4
- y = 12(x - 19) + 5
First, simplify
y = 12x - 228 + 5
y = 12x - 223
By comparison,
m = 12
∴ Slope = 12
y - 3 = 1/2(x - 4)
First, simplify
y - 3= (1/2)x - 2
y = (1/2)x -2 + 3
y = (1/2)x + 1
By comparison,
m = 1/2
∴ Slope = 1/2
Now,
The slopes ordered from the least to greatest is
-3/4 < 1/2 < 3/4 < 12
Thus,
The equations ordered from the least to greatest is
y = (-3/4)x + 2
y - 3 = 1/2(x - 4)
3x - 4y = 7
y = 12(x - 19) + 5
Learn more on Order of equations here: https://brainly.com/question/9353038
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