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A 28.0 g sample of nitrogen gas combines completely with 6.0 g of hydrogen gas to form ammonia. What is the mass of ammonia formed?​

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CintiaSalazar

Taking into account the reaction stoichiometry, the mass of ammonia formed is 34 grams.

Reaction stoichiometry

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • N₂: 1 mole
  • H₂: 3 moles
  • NH₃: 2 moles

The molar mass of the compounds is:

  • N₂: 28 g/mole
  • H₂: 2 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂: 1 mole ×28 g/mole= 28 grams
  • H₂: 3 moles ×2 g/mole= 6 grams
  • NH₃: 2 moles ×17 g/mole= 34 grams

Mass of ammonia formed

In this case, by reaction stoichiometry, a 28.0 g sample of nitrogen gas combines completely with 6.0 g of hydrogen gas. So, the mass of ammonia formed is 34 grams.

In summary, by reaction stoichiometry, the mass of ammonia formed is 34 grams.

Learn more about the reaction stoichiometry:

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