The results of the equations are listed below:
- T' = 20 °C
- A ≈ 113.097 m²
- A = 100 ft²
- s = 312.5 mi
- C' = $ 120
- C' = $ 40
- s = 27.5 mi
- T' = 100 °C
- C' = $ 60
- A = 112 ft²
How to use equations to find required information?
In this problem we must make use of given formulas and substitute all known variables to determine all the required information:
Case 1
The temperature in Celsius scale in terms of the temperature in Fahrenheit scale is defined by the following formula:
T' = (5 / 9) · (T - 32)
T' = (5 / 9) · (68 - 32)
T' = 20 °C
Case 2
The area of the circle in terms of its radius is presented below:
A = π · r²
A = π · (6 m)²
A ≈ 113.097 m²
Case 3
The area of the triangle as a function of its base and its height is shown in the following formula:
A = 0.5 · b · h
A = 0.5 · (8 ft) · (25 ft)
A = 100 ft²
Case 4
The traveled distance is the product of the velocity and time:
s = v · t
s = (62.5 mi / h) · (5 h)
s = 312.5 mi
Case 5
The simple interest formula is equal to the product of the invested amount, interest rate and time divided by 100:
C' = (C · r · t) / 100
C' = [(300) · (5) · (8)] / 100
C' = $ 120
Case 6
C' = (C · r · t) / 100
C' = [(200) · (2) · (10)] / 100
C' = $ 40
Case 7
s = v · t
s = (45 mi / h) · (0.5 h)
s = 27.5 mi
Case 8
T' = (5 / 9) · (T - 32)
T' = (5 / 9) · (212 - 32)
T' = 100 °C
Case 9
C' = (C · r · t) / 100
C' = [(1200) · (2.5) · (2)] / 100
C' = $ 60
Case 10
The area of the rectangle is equal to the product of its base and its height:
A = b · h
A = (14 ft) · (8 ft)
A = 112 ft²
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