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I need some serious help, i do not understand this question!!

An Alaskan rescue plane traveling 47 m/s
drops a package of emergency rations from
a height of 179 m to a stranded party of
explorers.
The acceleration of gravity is 9.8 m/s^2
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m.


Sagot :

The position where the package strikes the ground is 136.3m.

Time of motion of the package

Use the following kinematic equation;

h = vt + ¹/₂gt²

179 = 47t  +  ¹/₂(9.8)t²

179 = 47t + 4.9t²

4.9t² + 47t - 179 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 47, c = -179

t = 2.9 seconds

Horizontal distance traveled by the package

X = vt

X = 47m/s x 2.9 s

X = 136.3 m

Thus, the position where the package strikes the ground is 136.3m.

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