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Sagot :
Answer:
22
Step-by-step explanation:
Simply substitute x = 5 in the function equation
h(5) = 4 (5) + 2 = 20 + 2 = 22
Given ~
[tex] \tt \: h(x) = 4x + 2[/tex]
[tex] \: [/tex]
put the value of x = 5 in given function ~
[tex] \tt \: h(5) = 4(5) + 2[/tex]
[tex] \: [/tex]
[tex] \tt \: h(5) = 20 + 2[/tex]
[tex] \: [/tex]
[tex] \underline{ \boxed{ \tt\red{h(5) = 22}}}{ \green ✓}[/tex]
[tex] \: [/tex]
hope helps ~
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