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Sagot :
Let the number of sweets Mrs. Chua has be x
And the number of children be y
So,
x-8y=3 ------- 1️⃣
x-9y= -2 ------- 2️⃣
Change the signs of equation 2️⃣
x-8y=3
+x-9y=-2
- + +
__________
- y = 5 ----- 3️⃣
Substitute equation 3️⃣ in equation 1️⃣ :
[tex] \sf \: x - 8y = 3[/tex]
[tex] \sf \: x - 8 \times 5 = 3[/tex]
[tex] \sf \: x - 40 = 3[/tex]
[tex] \sf \: x = 3 + 40[/tex]
[tex] \tt \: x = 43[/tex]
Therefore, The total number of children i.e. y is 5 and the total number of sweets Mrs. Chua i.e. x is 43...
- The extra number of sweets required by Mrs. Chua is 2 because when each child gets 9 Mrs Chua has 2 sweets short...
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