Answered

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Find two numbers which differ by 4 and whose product is 45

Sagot :

wegnerkolmp2741o

Answer:

The two solutions are

5 and 9

-5 and -9

Step-by-step explanation:

Let x and y be the numbers

x-y = 4

x*y = 45

Using substitution

x = 4+y

(4+y)y =45

4y + y^2 = 45

Subtract 45 from each side

y^2 +4y -45 =0

Factor

(y - 5) ( y+9) = 0

Using the zero product property

y -5 =0    y+9 =0

y=5    y = -9

Now we can find x

y=5

x = 4+y

x =4+5

x=9

y = -9

x = 4+y

x = 4+-9

x = -5

The two solutions are

5 and 9

-5 and -9

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