Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A badger is trying to cross the street. Its velocity vvv as a function of time ttt is given in the graph below where rightwards is the positive velocity direction. A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5). A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5). What is the badger's displacement \Delta xΔxdelta, x from t=2\,\text st=2st, equals, 2, start text, s, end text to 3\,\text s3s3, start text, s, end text? Answer with two significant digits. \text mm

Sagot :

The badgers displacement from its position at point t = 2, to its position at point t = 3 is 25 meters

Which method can be used to calculate the displacement of the badger?

The points on the graph are;

(0, 0), (1, 5), (3, -5), (6, -5)

The point t = 2 is between (1, 5) and (3, -5)

The slope, m, of the line containing the point t = 2 is therefore;

  • m = (-5 - 5)/(3 - 1) = -5

The equation of the line is therefore;

v - 5 = -5•(t - 1)

v = -5•t + 5 + 5 = -5•t + 10

v = -5•t + 10

At t = 2, we have;

v = -5×2 + 10 = 0

The velocity at t = 2 is 0 m/s

The value of the acceleration is the same as the slope, m = a = -5

Given that the initial velocity at t = 2 is 0, we have;

∆x = u•t + 0.5•a•t²

At t = 3, the time of travel from the time t = 2 is 1 seconds, which gives;

∆x = 0×5 + 0.5×(-5)×1² = -2.5

The distance traveled between points, t = 2 and t = 3 is ∆x = -2.5, which is 2.5 meters in the direction opposite to the initial direction.

Learn more about the equations of motion here:

https://brainly.com/question/21010554

#SPJ1

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.