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Triangle ABC is a right triangle and cos(22.6o)=StartFraction b Over 13 EndFraction. Solve for b and round to the nearest whole number.

Triangle A B C is shown. Angle A C B is 90 degrees and angle C A B is 22.6 degrees. The length of hypotenuse A B is 13 centimeters, the length of A C is b, and the length of C B is a.

Which equation correctly uses the value of b to solve for a?

tan(22.6o) = StartFraction a Over 13 EndFraction
tan(22.6o) = StartFraction 13 Over a EndFraction
tan(22.6o) = StartFraction a Over 12 EndFraction
tan(22.6o) = StartFraction 12 Over a EndFraction

Sagot :

In the given triangle ABC right angled at C and [tex]AC = b[/tex] and [tex]CB = a[/tex], the equation using value of b used for solving for a will be [tex]tan(22.6degrees) = \frac{a}{12}[/tex].

According to the question statement, Triangle A B C is shown. Angle A C B is [tex]90[/tex] degrees and angle C A B is [tex]22.6[/tex] degrees. The length of hypotenuse A B is [tex]13[/tex] centimeters, the length of A C is b, and the length of C B is a.

We are supposed to find the equation using value of b used for solving for a.

Solution: Given,

  [tex]AB = 13cm\\AC = b\\BC = a\\Angle BAC = 22.6degrees[/tex]

If hypotenuse is 13cm then value of b is either 5 or 12 as per Pythagorean Triplet. As there is no value such as 5 in the given options we take the value of [tex]b=12 cm[/tex].

[tex]cos(22.6degrees) = \frac{b}{13} =\frac{12}{13} \\sin(22.6degrees) = \frac{a}{13}\\[/tex]

Using the above two equations,

[tex]tan(22.6degrees)=\frac{a}{b} \\b=12\\tan(22.6degrees)=\frac{a}{12}[/tex]

Therefore option three "tan(22.6o) = StartFraction a Over 12 EndFraction" is the correct answer.

  • Pythagorean Triplet: If a, b and c are three sides of a right angled triangle, c being the hypotenuse then [tex]a^{2} +b^{2} =c^{2}[/tex] and a and b being either of the base and perpendicular.

To learn more about Pythagoras theorem, click on the link given below:

https://brainly.com/question/343682

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