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2 1 Find the equation of the line that passes through the point (-4,16) and is perpendicular to the line y =
[tex] \frac{2}{5}x - \frac{1}{5} [/tex]
the equation using the slope-intercept form. Write the equation using slope intercept form​

Sagot :

rafikiedu14

Answer: Equation using slope intercept from y= -(5/2)x +26

Step-by-step explanation:

Write an equation of the line (in slope-intercept form) that is perpendicular to the line y=(2/5)x-(1/5) and contains the point (-4,16).

The line given is y=(2/5)x-(1/5)

Which we can rewrite in y= mx+b form as

y=(2/5)x-(1/5)

So slope of this line is (2/5)

A line perpendicular will have slope = -(5/2) ,  Which is (1/m)

Equation of new line will be

y = -(5/2)x +b

Now we need to find b

Plug in Point (-4,16)

Replace with the (-4,16) values

16 = (5/2) (-4) +b

solve it, 16=(-10)+b

16+10=b

b=26

Equation using slope intercept from y= -(5/2)x +26

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