michaelyayeh
Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

1, Let a = 2i-3j +4k and b = 2i+4k
a) Find the Projection of a "a" long "b"
b) Find the Projection of "b" along "a"​

Sagot :

The Projection of "a" along "b" is [tex]\sqrt{20}[/tex] and the Projection of "b" on "a" is [tex]\frac{20}{\sqrt{29} }[/tex]

Given that a = 2i-3j +4k and b = 2i+4k

To find Projection,

Projection of "x" on "Y"=(X vector).(Y unit vecot)

Projection of "a" along "b" =  (a vector).(b unit vector)

Projection of "a" along "b" = ( 2i-3j +4k).([tex]\frac{2i+4k}{\sqrt{29} }[/tex])

Projection of "a" along "b" =[tex]\frac{4+16}{\sqrt{20} }[/tex]

Projection of "a" along "b" =[tex]\frac{20}{\sqrt{20} }[/tex]

Projection of "a" along "b" =[tex]\sqrt{20}[/tex]

Projection of "b" along "a" =  (b vector).(a unit vector)

Projection of "b" along "a" = ( 2i+4k).([tex]\frac{2i-3j +4k}{\sqrt{29} }[/tex])

Projection of "b" along "a" = [tex]\frac{20}{\sqrt{29} }[/tex]

Therefore,The Projection of "a" along "b" is [tex]\sqrt{20}[/tex] and the Projection of "b" on "a" is [tex]\frac{20}{\sqrt{29} }[/tex]

Learn more about Projection here:

https://brainly.com/question/15999858

#SPJ9

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.