Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

ST
Problem number 26 of the Rhind Papyrus says:
Find a quantity such that when it is added to of itself
the result is a 15.

The modern day equation that models this problem is
x+x=15.

What is the solution to the equation?
O x = 10

x = 12


x = 15
x = 30

Sagot :

reinhard10158

Step-by-step explanation:

please make sure that fractions are still in the problem text after scanning it.

because they are missing here, and I have to guess around.

Basically the problem is

x + 1/a × x = 15

that means

ax + x = 15a

(a+1)x = 15a

x = 15a/(a+1)

for a = 2 (so, 1/2 x is added to x), we get

x = 15×2/3 = 30/3 = 10

for a = 4 (1/4 of x is added to x), we get

x = 15×4/5 = 60/5 = 12

these are also the first 2 answer options. so, please pick the one that fits the complete problem definition.

the 3rd and 4th answer options are nonsense anyway, as when you add something greater than 0 to x and get 15, then the initial x cannot be already 15 or even bigger.

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.