Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

ST
Problem number 26 of the Rhind Papyrus says:
Find a quantity such that when it is added to of itself
the result is a 15.

The modern day equation that models this problem is
x+x=15.

What is the solution to the equation?
O x = 10

x = 12


x = 15
x = 30

Sagot :

reinhard10158

Step-by-step explanation:

please make sure that fractions are still in the problem text after scanning it.

because they are missing here, and I have to guess around.

Basically the problem is

x + 1/a × x = 15

that means

ax + x = 15a

(a+1)x = 15a

x = 15a/(a+1)

for a = 2 (so, 1/2 x is added to x), we get

x = 15×2/3 = 30/3 = 10

for a = 4 (1/4 of x is added to x), we get

x = 15×4/5 = 60/5 = 12

these are also the first 2 answer options. so, please pick the one that fits the complete problem definition.

the 3rd and 4th answer options are nonsense anyway, as when you add something greater than 0 to x and get 15, then the initial x cannot be already 15 or even bigger.

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.