Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
When 10.0 g of NaCl is added to an aqueous solution of AgNO₃, 24.5 g AgCl will be precipitated.
The balanced chemical reaction is:
NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)
Molar mass of NaCl = 58.5 g
Molar mass of AgCl = 143.5 g
Number of moles of NaCl = Given Mass
Molecular Mass
= 10.0 g ÷ 58.44 g/mol
= 0.171 moles
From the reaction,
58.5 g of NaCl produces 143.5 g of AgCl
10.0 g of NaCl will produce 143.5 × 10.0 = 24.5 g AgCl
58.5
To learn more about precipitation reactions,
https://brainly.com/question/14260390
#SPJ4
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
