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Sagot :
The minimum speed the ball must be served so as to clear the net is 25.69 m / s
We know that,
Speed = Distance / Time
In order to calculate the time, we can use one of the equations of motion,
y = [tex]y_{0}[/tex] + [tex]v_{0}[/tex]t + 1/2 a[tex]t^{2}[/tex]
where,
y = Initial height
[tex]y_{0}[/tex] = Final height
[tex]v_{0}[/tex] = Initial velocity
a = Acceleration due to gravity
t = Time
Given that,
y = 2.7 m
[tex]y_{0}[/tex] = 1.08 m
[tex]v_{0}[/tex] = 0
a = -9.81 m / [tex]s^{2}[/tex] (Due to gravity)
Distance = 14.9 m
y = [tex]y_{0}[/tex] + [tex]v_{0}[/tex]t + 1/2 a[tex]t^{2}[/tex]
2.7 = 1.08 + 0 + 1/2 * ( -9.81 ) * [tex]t^{2}[/tex]
[tex]t^{2}[/tex] = 1.62 / ( - 4.9 ) = 0.33
t = 0.58 s
Speed = 14.9 / 0.58
Speed = 25.69 m / s
Velocity (speed) is the rate of change of distance with respect to time. It is denoted as V.
Therefore, the minimum speed the ball must be served so as to clear the net is 25.69 m / s
To know more about Velocity
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