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Sagot :
Work input is required in each cycle w = 208j
Here can explain as ,according to the law of conservation of energy , the total heat given off the surrounding by a refrigerator is equal to the work done by the refrigerator and the heat removed from the inside of a refrigerator .i.e. the addition of heat removed or absorbs and work done by the refrigerator is equal to the heat expelled to the room during each cycle. It can be shown as ,
[tex]Q_{h}[/tex] =[tex]Q_{c}[/tex] + [tex]W[/tex]
Where,
[tex]W[/tex] is work input of refrigerator during each cycle.
[tex]Q_{c}[/tex] is the heat removed or absorbed by the refrigerator.
[tex]Q_{h}[/tex] is heat expelled to the room during each cycle.
Given here,
[tex]Q_{c}[/tex] = 257 j
[tex]Q_{h}[/tex] = 465 j
Therefore from above equation can be find the value of work input by the refrigerator in each cycle,
[tex]W[/tex] =[tex]Q_{h}[/tex] - [tex]Q_{c}[/tex]
w = (465 j) -(257 j)
w= 208j
To know more about refrigerator.
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