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What depth of oil, specific gravity of 0.750, will produce a pressure of 46 psig?

Sagot :

The depth of oil is 43 m

We know that

P = ρ g h

where,

P = Pressure of fluid

ρ = Density of fluid

g = Acceleration due to gravity

h = Depth of fluid

Given that,

P = 46 psig = 3.2 * [tex]10^{5}[/tex] N / [tex]m^{2}[/tex]

s = 0.75

ρ = 0.75 * 1000 = 750 kg / [tex]m^{3}[/tex]

g = 9.81 m / [tex]s^{2}[/tex]

Here we round the value of g = 10 m / [tex]s^{2}[/tex]

h = P / ρ g

h = ( 3.2 * [tex]10^{5}[/tex] ) / ( 750 * 10 ) = 42.67 m

h = 43 m

Fluid pressure is the measurement of force per unit area that acts on an object in the fluid.

Therefore, the depth of oil is 43 m

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