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How many h atoms are in 259 g of c12h21o9? molar mass of c12h21o9 = 309.29 g/mol

Sagot :

Number if atoms in 259 g of [tex]C_12H_2_1O_9[/tex] is  [tex]5.04*10^{23}[/tex]

                                                 

We know that according to Avogadro's law , number of atoms in one mole of molecule is [tex]6.022*10^{23}[/tex] .

In given question we have to find number of atoms in 259 g of [tex]C_12H_2_1O_9[/tex]

The molar mass of [tex]C_12H_2_1O_9[/tex] is given that is [tex]309.29 g/mol[/tex]

Therefore total number of moles =  [tex]given mass / molar mass[/tex]

Number of moles                         = [tex]259/309.29[/tex]

                                                       =[tex]0.8374[/tex]

Thus, number of atoms in 0.8374 mole of [tex]C_12H_2_1O_9[/tex] is given by

                                                        = [tex]0.8374 * 6.022 * 10^{23}[/tex]

                                                        = [tex]5.04*10^{23}[/tex]

To know more about Avogadro's law

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