Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A solution is made by mixing 11.g of water and 72.g of acetic acid hch3co2. calculate the mole fraction of water in this solution. round your answer to 2 significant digits.

Sagot :

The Mole fraction of Water in this solution is 0.34

We know that,

Mole Fraction of Water = No. of moles of Water / Total number of moles of the solution

No. of moles = Mass / Molar mass

Given that,

Mass of Water = 11g

Mass of Acetic acid = 72g

Molar mass of Water = 18.015 g/mol

Molar mass of Acetic acid = 60.052 g/mol

No. of moles of Water= 11 / 18.015= 0.611 moles

No. of moles of Acetic acid = 72 / 60.052= 1.199 moles

Total no. of moles = 0.611+ 1.199 = 1.81 moles

Mole fraction of chloroform = 0.611 / 1.81 = 0.338

In a solution containing at least 2 components, the number of moles of one component divided by total number of moles in that solution is called  Mole fraction.

Therefore, the Mole fraction of Water in this solution is 0.34

To know more about Mole fraction

brainly.com/question/14469503

#SPJ4