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Kayla has a red number cube and a blue number cube. Each number cube has faces labeled 1 through 6.
What is the probability Kayla rolls an even number on the red cube and a multiple of 3 on the blue cube?

Sagot :

So probability that kayla rolls an even number on the red cube and a multiple of 3 on the blue cube is 16.66 ≈ 16%

Given that we have red number cube and blue number cube so as we all know that Probability is the ratio of the favourable number of outcomes to the total number of outcomes is known as Probability.

First, find the possible outcomes.

Kalya has a red number cube and a blue number cube. Each number cube has faces labeled 1 through 6

So, possible outcomes =6×6 =36

Let, S be the sample space.

Then, ⁿ(s) =36

Let, E = the event of getting an even number on the red cube and a multiple of  on the blue cube.

E = (2,3),(2,6),(4,3),(6,3),(6,6)

Then,  ⁿ(E)=6

Let, P  is the probability of the event .

So, P(E)= [tex]\frac{n(E)}{n(S)}[/tex] = [tex]\frac{6}{36}[/tex] = [tex]\frac{1}{6}[/tex] = 16.67 percent or 16[tex]\frac{2}{3}[/tex]  %

Thus, the probability Kayla rolls an even number on the red cube and a multiple of  on the blue cube is 16.66 percent.

Learn more about Probability here: brainly.com/question/16512300

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Answer:

16%

Step-by-step explanation: