Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
So probability that kayla rolls an even number on the red cube and a multiple of 3 on the blue cube is 16.66 ≈ 16%
Given that we have red number cube and blue number cube so as we all know that Probability is the ratio of the favourable number of outcomes to the total number of outcomes is known as Probability.
First, find the possible outcomes.
Kalya has a red number cube and a blue number cube. Each number cube has faces labeled 1 through 6
So, possible outcomes =6×6 =36
Let, S be the sample space.
Then, ⁿ(s) =36
Let, E = the event of getting an even number on the red cube and a multiple of on the blue cube.
E = (2,3),(2,6),(4,3),(6,3),(6,6)
Then, ⁿ(E)=6
Let, P is the probability of the event .
So, P(E)= [tex]\frac{n(E)}{n(S)}[/tex] = [tex]\frac{6}{36}[/tex] = [tex]\frac{1}{6}[/tex] = 16.67 percent or 16[tex]\frac{2}{3}[/tex] %
Thus, the probability Kayla rolls an even number on the red cube and a multiple of on the blue cube is 16.66 percent.
Learn more about Probability here: brainly.com/question/16512300
#SPJ9
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
