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Ca(s) + O₂(g) + S(s) → CaSO4(s)
[?] g 6.400 g 3.206 g 13.614 g
According to the law of conservation of
mass, what is the mass of calcium, Ca,
required to complete this reaction?
Use the correct same precision for the
missing value. (i.e. significant figures).
Help Res

Sagot :

bharathparasad577

The mass of Calcium required to complete this reaction is 4.008 g.

  • Law of conservation of mass states that In a closed system, mass cannot be produced or destroyed, but it can be changed from one form to another.
  • The mass of the chemical constituents before a chemical reaction is equal to the mass of the constituents after the reaction.
  • In several disciplines, including chemistry, mechanics, and fluid dynamics, the idea of mass conservation is widely applied.

In the given reaction mass of product after completion of reaction is 13.614 g that means total mass of constituents before reaction should also be 13.614.

So,

mass of Ca + mass of O₂ + mass of S = mass of CaSO4

Ca + 6.400 g + 3.206 g = 13.614 g

mass of Ca = 13.614 - 9.606 = 4.008 g

Therefore, by law of conservation of mass 4.008 g of Ca is required for the completion of the reaction.

Learn more about mass conservation here:

https://brainly.com/question/2030891

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