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A ball is thrown vertically downward with an initial speed of 15.8 m/s from a building whose height is 122 m. how long does it take for the ball to strike the ground?

Sagot :

A ball is thrown vertically downward with an initial speed of 15.8 m/s from a building whose height is 122 m. It takes the ball 3.63 s to strike the ground.

Vertical Motion:

Because the object is moving downhill vertically, the motion has a negative acceleration value as well as a negative velocity value.

A quadratic function with concavity downwards can be used to represent both this kind of motion and the motion of the object thrown above.

Answer and justification

h = h0 - v0t - [tex]\frac{gt^2}{2}[/tex]

so putting all the values, we have,

0 = 122 - 15.8t - 4.9 [tex]t^{2}[/tex]

then we know the formula,

t= [tex]\frac{-b±\sqrt{b^2-4ac}}{2a}[/tex] here a=-4.9 b= -15.8 c =122

now putting all the values, we have

t= 3.63 s

So, In 3.63 seconds, the ball lands on the ground.

To know more about Vertical motion visit:

https://brainly.com/question/12640444

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