Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The probability of a red light be on this road so that neither road would be preferred over the other on the basis of expected number of red lights is 0.3375.
What is Probability:
Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one. Probability has been introduced in Math's to predict how likely events are to happen. The meaning of probability is basically the extent to which something is likely to happen. This is the basic probability theory, which is also used in the probability distribution, where you will learn the possibility of outcomes for a random experiment. To find the probability of a single event to occur, first, we should know the total number of possible outcomes.
Now,
PDF of a Binomial (n, x) distribution is
given as
p(X=x).[tex]C^n_x P^x (1-p)^(n-x)[/tex] x = 0,1,2,
Here n = 9, 2:4, p = 0.3
P(x-4)= 9^c_4(0.3)^4 (0.75)^5 = 0·1715 Ans
R Code
We will use the function pGnom() which gives the Cumulative probability of an
Probability of getting exactly 4 heads is
x <- pGnom (4,9, 0.3) - pGnom (3,9, 0.3)
(We substract 3 to get P(X = 4) since above we have P(X<4) - P(X ≤3)
b)
Expected number in a binomial distribution = np
We have to equate the Expected values
So
9x0.3 = 8xp
os, p = 0.3375.
To know more about "Probability"
Refer this link:
https://brainly.com/question/13604758
#SPJ4
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.